18=2x^2-x

Solution for 18=2x^2-x equation:

18=2x^2-x

We move all terms to the left:

18-(2x^2-x)=0

We get rid of parentheses

-2x^2+x+18=0

a = -2; b = 1; c = +18;
Δ = b2-4ac
Δ = 12-4·(-2)·18
Δ = 145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{145}}{2*-2}=\frac{-1-\sqrt{145}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{145}}{2*-2}=\frac{-1+\sqrt{145}}{-4}
$